Ian Lynagh c241b081cb C++: Don't unresolve 'this'
For example, if you have 3 types called T, where t1 and t2 are defined
but t3 isn't, then you will have

    unspecifiedtype(t1, t1)
    unspecifiedtype(t2, t2)
    unspecifiedtype(t3, t3)

    t1 = resolve(t1)
    t1 = resolve(t3)
    t2 = resolve(t2)
    t2 = resolve(t3)

so given

    Type getUnspecifiedType() {
        unspecifiedtype(unresolve(this), unresolve(result))
    }

you get t1.getUnspecifiedType() = t2.

I think that in general the best thing to do is to not unresolve 'this',
but to just take the underlying value.
2018-08-20 16:12:26 +01:00
2018-08-20 16:12:26 +01:00
2018-08-07 12:19:02 +01:00
2018-08-15 12:32:54 +01:00

Semmle QL

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