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C++: Fix FPs caused by a syntax error
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@@ -16,6 +16,20 @@
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import cpp
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class SyntaxError extends CompilerError {
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SyntaxError() { this.getTag().matches("exp_%") }
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predicate affects(Element e) {
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exists(Location l1, Location l2 |
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l1 = this.getLocation() and
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l2 = e.getLocation()
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l1.getFile() = l2.getFile() and
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l1.getStartLine() = l2.getStartLine()
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)
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}
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}
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from FormatLiteral fl, FormattingFunctionCall ffc, int expected, int given, string ffcName
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where
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ffc = fl.getUse() and
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@@ -27,7 +41,10 @@ where
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if ffc.isInMacroExpansion()
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then ffcName = ffc.getTarget().getName() + " (in a macro expansion)"
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else ffcName = ffc.getTarget().getName()
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)
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) and
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// A typical problem is that string literals are concatenated, but if one of the string
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// literals is an undefined macro, then this just leads to a syntax error.
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not exists(SyntaxError e | e.affects(fl))
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select ffc,
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"Format for " + ffcName + " expects " + expected.toString() + " arguments but given " +
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given.toString()
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@@ -5,7 +5,6 @@
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| macros.cpp:14:2:14:37 | call to printf | Format for printf (in a macro expansion) expects 4 arguments but given 3 |
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| macros.cpp:21:2:21:36 | call to printf | Format for printf (in a macro expansion) expects 4 arguments but given 3 |
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| macros.cpp:32:2:32:25 | call to printf | Format for printf (in a macro expansion) expects 1 arguments but given 0 |
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| syntax_errors.c:6:5:6:10 | call to printf | Format for printf expects 1 arguments but given 0 |
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| test.c:9:2:9:7 | call to printf | Format for printf expects 1 arguments but given 0 |
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| test.c:12:2:12:7 | call to printf | Format for printf expects 2 arguments but given 1 |
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| test.c:15:2:15:7 | call to printf | Format for printf expects 3 arguments but given 2 |
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