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38 lines
1.2 KiB
Plaintext
38 lines
1.2 KiB
Plaintext
/**
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* @name Modification of dictionary returned by locals()
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* @description Modifications of the dictionary returned by locals() are not propagated to the local variables of a function.
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* @kind problem
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* @tags reliability
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* correctness
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* @problem.severity warning
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* @sub-severity low
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* @precision very-high
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* @id py/modification-of-locals
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*/
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import python
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predicate originIsLocals(ControlFlowNode n) { n.pointsTo(_, _, Value::named("locals").getACall()) }
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predicate modification_of_locals(ControlFlowNode f) {
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originIsLocals(f.(SubscriptNode).getObject()) and
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(f.isStore() or f.isDelete())
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or
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exists(string mname, AttrNode attr |
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attr = f.(CallNode).getFunction() and
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originIsLocals(attr.getObject(mname))
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mname in ["pop", "popitem", "update", "clear"]
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)
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}
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from AstNode a, ControlFlowNode f
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where
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modification_of_locals(f) and
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a = f.getNode() and
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// in module level scope `locals() == globals()`
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// see https://docs.python.org/3/library/functions.html#locals
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// FP report in https://github.com/github/codeql/issues/6674
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not a.getScope() instanceof ModuleScope
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select a, "Modification of the locals() dictionary will have no effect on the local variables."
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