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codeql/csharp
Tom Hvitved dd99525566 C#: Redefine AccessorCall
The syntactic node assiociated with accessor calls was previously always the
underlying member access. For example, in

```
x.Prop = y.Prop;
```

the implicit call to `x.set_Prop()` was at the syntactic node `x.Prop`, while the
implicit call to `y.get_Prop()` was at the syntactic node `y.Prop`.

However, this breaks the invariant that arguments to calls dominate the call itself,
as the argument `y.Prop` for the implicit `value` parameter in `x.set_Prop()` will
be evaluated after the call (the left-hand side in an assignment is evaluated before
the right-hand side).

The solution is to redefine the access call to `x.set_Prop()` to point to the whole
assignment `x.Prop = y.Prop`, instead of the access `x.Prop`. For reads, we still want
to associate the accessor call with the member access.

A corner case arises when multiple setters are called in a tuple assignment:

```
(x.Prop1, x.Prop2) = (0, 1)
```

In this case, we cannot associate the assignment with both `x.set_Prop1()` and
`x.set_Prop2()`, so we instead revert to using the underlying member accesses as
before.
2019-01-18 13:56:23 +01:00
..
2019-01-11 16:13:04 +00:00
2019-01-18 13:56:23 +01:00
2018-11-07 08:52:38 +01:00