Files
codeql/python/ql/src/Numerics/Pythagorean.ql
Taus d4fc096ea8 Python: Use local flow in Pythagorean.ql
The hand-rolled notion of flow was causing some severe performance
issues (on a few databases):

```
Tuple counts for Pythagorean::square#168e234a#f#loop_invariant_prefix/2@c86989kr after 6m35s:
175000     ~5%     {2} r1 = JOIN SSA::SsaVariable::getDefinition#dispred#f0820431#ff_10#join_rhs WITH Flow::ControlFlowNode::getNode#dispred#f0820431#bf ON FIRST 1 OUTPUT Lhs.1, Rhs.1 'arg0'
174500     ~6%     {2} r2 = JOIN r1 WITH SSA::SsaVariable::getVariable#dispred#f0820431#ff ON FIRST 1 OUTPUT Rhs.1, Lhs.1 'arg0'
1467782500 ~5%     {3} r3 = JOIN r2 WITH AstGenerated::Name_::getVariable#dispred#f0820431#ff_10#join_rhs ON FIRST 1 OUTPUT 3, Rhs.1 'arg1', Lhs.1 'arg0'
1467553000 ~0%     {2} r4 = JOIN r3 WITH py_expr_contexts_12#join_rhs ON FIRST 2 OUTPUT Lhs.2 'arg0', Lhs.1 'arg1'
                    return r4
```

Rewriting it to use the data flow library made all of this go away. 🎉
2022-04-25 14:35:37 +00:00

40 lines
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/**
* @name Pythagorean calculation with sub-optimal numerics
* @description Calculating the length of the hypotenuse using the standard formula may lead to overflow.
* @kind problem
* @tags accuracy
* @problem.severity warning
* @sub-severity low
* @precision medium
* @id py/pythagorean
*/
import python
import semmle.python.dataflow.new.DataFlow
import semmle.python.ApiGraphs
DataFlow::ExprNode squareOp() {
exists(BinaryExpr e | e = result.asExpr() |
e.getOp() instanceof Pow and e.getRight().(IntegerLiteral).getN() = "2"
)
}
DataFlow::ExprNode squareMul() {
exists(BinaryExpr e | e = result.asExpr() |
e.getOp() instanceof Mult and e.getRight().(Name).getId() = e.getLeft().(Name).getId()
)
}
DataFlow::ExprNode square() { result in [squareOp(), squareMul()] }
from DataFlow::CallCfgNode c, BinaryExpr s, DataFlow::ExprNode left, DataFlow::ExprNode right
where
c = API::moduleImport("math").getMember("sqrt").getACall() and
c.getArg(0).asExpr() = s and
s.getOp() instanceof Add and
left.asExpr() = s.getLeft() and
right.asExpr() = s.getRight() and
left.getALocalSource() = square() and
right.getALocalSource() = square()
select c, "Pythagorean calculation with sub-optimal numerics"