Files
codeql/python/ql/src/experimental/Security/CWE-285/PamAuthorizationGood.py
Porcupiney Hairs 92033047a5 Python : Add query to detect PAM authorization bypass
Using only a call to `pam_authenticate` to check the validity of a login can
lead to authorization bypass vulnerabilities. A `pam_authenticate` only
verifies the credentials of a user. It does not check if a user has an
appropriate authorization to actually login. This means a user with a
expired login or a password can still access the system.

This PR includes a qhelp describing the issue, a query which detects instances where a call to
`pam_acc_mgmt` does not follow a call to `pam_authenticate` and it's
corresponding tests.

This PR has multiple detections. Some of the public one I can find are :
* [CVE-2022-0860](https://nvd.nist.gov/vuln/detail/CVE-2022-0860) found
in [cobbler/cobbler](https://www.github.com/cobbler/cobbler)
* [fredhutch/motuz](https://www.huntr.dev/bounties/d46f91ca-b8ef-4b67-a79a-2420c4c6d52b/)
2022-03-30 00:47:58 +05:30

17 lines
661 B
Python

def authenticate(self, username, password, service='login', encoding='utf-8', resetcreds=True):
libpam = CDLL(find_library("pam"))
pam_authenticate = libpam.pam_authenticate
pam_acct_mgmt = libpam.pam_acct_mgmt
pam_authenticate.restype = c_int
pam_authenticate.argtypes = [PamHandle, c_int]
pam_acct_mgmt.restype = c_int
pam_acct_mgmt.argtypes = [PamHandle, c_int]
handle = PamHandle()
conv = PamConv(my_conv, 0)
retval = pam_start(service, username, byref(conv), byref(handle))
retval = pam_authenticate(handle, 0)
if retval == 0:
retval = pam_acct_mgmt(handle, 0)
return retval == 0