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Migrate 27 queries under python/ql/src/ from legacy CFG types (CallNode/AttrNode/NameNode/etc.) to the shared-CFG-based 'Cfg::' namespace, matching the dataflow API surface introduced earlier on this branch. ModificationOfParameterWithDefaultCustomizations.qll is rewritten on top of BarrierGuard, removing the last legacy ESSA dependency in that file. UnguardedNextInGenerator.ql still uses ESSA and bridges to the new CFG via Cfg::CallNode.getNode(). Also reformat 14 library and query files that had drifted from the formatter. Co-authored-by: Copilot <223556219+Copilot@users.noreply.github.com>
46 lines
1.5 KiB
Plaintext
46 lines
1.5 KiB
Plaintext
/**
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* @name Modification of dictionary returned by locals()
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* @description Modifications of the dictionary returned by locals() are not propagated to the local variables of a function.
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* @kind problem
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* @tags quality
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* reliability
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* correctness
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* @problem.severity warning
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* @sub-severity low
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* @precision very-high
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* @id py/modification-of-locals
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*/
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import python
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private import semmle.python.ApiGraphs
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private import semmle.python.controlflow.internal.Cfg as Cfg
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predicate originIsLocals(Cfg::ControlFlowNode n) {
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API::builtin("locals").getReturn().getAValueReachableFromSource().asCfgNode() = n
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}
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predicate modification_of_locals(Cfg::ControlFlowNode f) {
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originIsLocals(f.(Cfg::SubscriptNode).getObject()) and
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(f.isStore() or f.isDelete())
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or
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exists(string mname, Cfg::AttrNode attr |
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attr = f.(Cfg::CallNode).getFunction() and
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originIsLocals(attr.getObject(mname))
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mname in ["pop", "popitem", "update", "clear"]
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)
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}
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from AstNode a, Cfg::ControlFlowNode f
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where
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modification_of_locals(f) and
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a = f.getNode() and
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// in module level scope `locals() == globals()`
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// see https://docs.python.org/3/library/functions.html#locals
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// FP report in https://github.com/github/codeql/issues/6674
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not a.getScope() instanceof Module and
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// in class level scope `locals()` reflects the class namespace,
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// so modifications do take effect.
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not a.getScope() instanceof Class
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select a, "Modification of the locals() dictionary will have no effect on the local variables."
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