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ddf1ef8a7d
We now output literals for accesses to members of template parameters:
So for `foo` in the following example:
```
template<typename T> void bar(T& t) {
T.foo(1)
}
```
20 lines
151 B
C++
20 lines
151 B
C++
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class A {
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public:
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void foo();
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int k;
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};
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class B {
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public:
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template <typename T>
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B(T x) {
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int k = x.k;
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x.foo();
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}
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};
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A a;
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B b(a);
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