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Python: simplify logic, suggested in review
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@@ -608,7 +608,7 @@ ControlFlowNode guardNode(ConditionBlock conditionBlock, boolean flipped) {
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// if a guard node is compared to a boolean literal,
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// the other operand is also a guard node,
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// but with polarity depending on the literal (and on the comparison).
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exists(CompareNode cmpNode, Cmpop op, ControlFlowNode b, boolean bool |
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exists(CompareNode cmpNode, Cmpop op, ControlFlowNode b, boolean should_flip |
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(
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cmpNode.operands(result, op, b) or
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cmpNode.operands(b, op, result)
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@@ -617,19 +617,19 @@ ControlFlowNode guardNode(ConditionBlock conditionBlock, boolean flipped) {
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(
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// comparing to the boolean
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(op instanceof Eq or op instanceof Is) and
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// `bool` is the value being compared against, here the value of `b`
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b.getNode().(BooleanLiteral).booleanValue() = bool
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// we shoould flip if the value compared against, here the value of `b`, is false
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should_flip = b.getNode().(BooleanLiteral).booleanValue().booleanNot()
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or
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// comparing to the negation of the boolean
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(op instanceof NotEq or op instanceof IsNot) and
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// again, `bool` is the value being compared against, but here it is the value of `not b`
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b.getNode().(BooleanLiteral).booleanValue() = bool.booleanNot()
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// again, we should flip if the value compared against, here the value of `not b`, is false.
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// That is, if the value of `b` is true.
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should_flip = b.getNode().(BooleanLiteral).booleanValue()
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)
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// if `bool` is true, we should preserve `flipped`, otherwise we should flip it
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// `flipped xor (not bool)` achieves that.
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// we flip `flipped` according to `should_flip` via the formula `flipped xor should_flip`.
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flipped in [true, false] and
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cmpNode = guardNode(conditionBlock, flipped.booleanXor(bool.booleanNot()))
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cmpNode = guardNode(conditionBlock, flipped.booleanXor(should_flip))
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)
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}
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