Add new experimental query MultipleArgumentsToSetConstructor.

This commit is contained in:
Max Schaefer
2021-05-21 09:54:41 +01:00
parent 922b276fac
commit 6e34784fc5
9 changed files with 98 additions and 0 deletions

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<!DOCTYPE qhelp PUBLIC
"-//Semmle//qhelp//EN"
"qhelp.dtd">
<qhelp>
<overview>
<p>
The <code>Set</code> constructor accepts an arbitrary number of arguments, but only the first one
is used to construct the set. The remaining arguments are ignored.
Code that invokes the <code>Set</code> constructor with multiple arguments is therefore likely to
be incorrect.
</p>
</overview>
<recommendation>
<p>
Only pass a single argument to the <code>Set</code> constructor, which should be an iterable object
(such as an array).
</p>
</recommendation>
<example>
<p>
The following example creates a set containing the vowels in the English language, and defines
a function that returns a boolean indicating whether a given character is a vowel:
</p>
<sample src="examples/MultipleArgumentsToSetConstructorBad.js"/>
<p>
However, this code does not work as intended: the <code>Set</code> constructor ignores all but
the first argument, so the <code>vowels</code> set only contains the letter <code>a</code>.
</p>
<p>
Instead, the list of vowels should be wrapped into an array:
</p>
<sample src="examples/MultipleArgumentsToSetConstructorGood.js"/>
</example>
<references>
<li><a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Set/Set">MDN Web Docs: Set() constructor</a></li>
</references>
</qhelp>

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/**
* @name Multiple arguments to `Set` constructor
* @description The `Set` constructor ignores all but the first argument, so passing multiple
* arguments may indicate a mistake.
* @kind problem
* @problem.severity warning
* @precision high
* @id js/multiple-arguments-to-set-constructor
* @tags correctness
*/
import javascript
from DataFlow::NewNode newSet, DataFlow::Node ignoredArg
where
newSet = DataFlow::globalVarRef("Set").getAnInstantiation() and
(
ignoredArg = newSet.getArgument(any(int n | n > 0))
or
ignoredArg = newSet.getASpreadArgument()
)
select ignoredArg, "All but the first argument to the Set constructor are ignored."

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const vowels = new Set('a', 'e', 'i', 'o', 'u');
function isVowel(char) {
return vowels.has(char.toLowerCase());
}

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const vowels = new Set(['a', 'e', 'i', 'o', 'u']);
function isVowel(char) {
return vowels.has(char.toLowerCase());
}