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Python: Promote xml.etree modeling

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Rasmus Wriedt Larsen
2022-03-31 10:42:05 +02:00
parent 7f5f7679f8
commit 64aa503cc3
4 changed files with 119 additions and 118 deletions
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45
python/ql/test/experimental/library-tests/frameworks/XML/xml_etree.py
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from io import StringIO
import xml.etree.ElementTree
x = "some xml"
# Parsing in different ways
xml.etree.ElementTree.fromstring(x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.fromstring(..)
xml.etree.ElementTree.fromstring(text=x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.fromstring(..)
xml.etree.ElementTree.fromstringlist([x]) # $ decodeFormat=XML decodeInput=List xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.fromstringlist(..)
xml.etree.ElementTree.fromstringlist(sequence=[x]) # $ decodeFormat=XML decodeInput=List xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.fromstringlist(..)
xml.etree.ElementTree.XML(x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.XML(..)
xml.etree.ElementTree.XML(text=x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.XML(..)
xml.etree.ElementTree.XMLID(x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.XMLID(..)
xml.etree.ElementTree.XMLID(text=x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.XMLID(..)
xml.etree.ElementTree.parse(StringIO(x)) # $ decodeFormat=XML decodeInput=StringIO(..) xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.parse(..)
xml.etree.ElementTree.parse(source=StringIO(x)) # $ decodeFormat=XML decodeInput=StringIO(..) xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.parse(..)
xml.etree.ElementTree.iterparse(StringIO(x)) # $ decodeFormat=XML decodeInput=StringIO(..) xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.iterparse(..)
xml.etree.ElementTree.iterparse(source=StringIO(x)) # $ decodeFormat=XML decodeInput=StringIO(..) xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.iterparse(..)
# With parsers (no options available to disable/enable security features)
parser = xml.etree.ElementTree.XMLParser()
xml.etree.ElementTree.fromstring(x, parser=parser) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup' decodeOutput=xml.etree.ElementTree.fromstring(..)
# manual use of feed method
parser = xml.etree.ElementTree.XMLParser()
parser.feed(x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup'
parser.feed(data=x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup'
parser.close() # $ decodeOutput=parser.close()
# manual use of feed method on XMLPullParser
parser = xml.etree.ElementTree.XMLPullParser()
parser.feed(x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup'
parser.feed(data=x) # $ decodeFormat=XML decodeInput=x xmlVuln='Billion Laughs' xmlVuln='Quadratic Blowup'
parser.close() # $ decodeOutput=parser.close()
# note: it's technically possible to use the thing wrapper func `fromstring` with an
# `lxml` parser, and thereby change what vulnerabilities you are exposed to.. but it
# seems very unlikely that anyone would do this, so we have intentionally not added any
# tests for this.