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Incorporate changes from Python PR
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@@ -9,39 +9,72 @@ private import codeql_ruby.ast.Literal as AST
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private import codeql.Locations
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class RegExp extends AST::RegExpLiteral {
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/** result is true for those start chars that actually mark a start of a char set. */
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/**
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* Helper predicate for `charSetStart(int start, int end)`.
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*
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* In order to identify left brackets ('[') which actually start a character class,
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* we perform a left to right scan of the string.
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*
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* To avoid negative recursion we return a boolean. See `escaping`,
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* the helper for `escapingChar`, for a clean use of this pattern.
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*
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* result is true for those start chars that actually mark a start of a char set.
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*/
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boolean charSetStart(int pos) {
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exists(int index |
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charSetDelimiter(index, pos) = true and
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// is opening bracket
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this.charSetDelimiter(index, pos) = true and
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(
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index = 1 and result = true // if a '[' is first in the string (among brackets), it starts a char set
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// if this is the first bracket, `pos` starts a char set
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index = 1 and result = true
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or
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// if the previous char set delimiter was not a closing bracket, `pos` does
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// not start a char set. This is needed to handle cases such as `[[]` (a
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// char set that matches the `[` char)
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index > 1 and
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not charSetDelimiter(index - 1, _) = false and
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not this.charSetDelimiter(index - 1, _) = false and
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result = false
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or
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exists(int p1 |
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charSetDelimiter(index - 1, p1) = false and // if it is preceded by a closing bracket, it starts a char set
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// special handling of cases such as `[][]` (the character-set of the characters `]` and `[`).
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exists(int prevClosingBracketPos |
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// previous bracket is a closing bracket
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this.charSetDelimiter(index - 1, prevClosingBracketPos) = false and
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if
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exists(int p2 |
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p1 = p2 + 1
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or
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this.getChar(p2 + 1) = "^" and
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p1 = p2 + 2
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// check if the character that comes before the previous closing bracket
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// is an opening bracket (taking `^` into account)
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// check if the character that comes before the previous closing bracket
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// is an opening bracket (taking `^` into account)
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exists(int posBeforePrevClosingBracket |
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if this.getChar(prevClosingBracketPos - 1) = "^"
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then posBeforePrevClosingBracket = prevClosingBracketPos - 2
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else posBeforePrevClosingBracket = prevClosingBracketPos - 1
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charSetDelimiter(index - 2, p2) = true // but the closing bracket only closes...
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this.charSetDelimiter(index - 2, posBeforePrevClosingBracket) = true
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)
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then
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exists(int p2 | charSetDelimiter(index - 2, p2) = true |
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result = charSetStart(p2).booleanNot() // ...if it is not the first in a char set
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// brackets without anything in between is not valid character ranges, so
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// the first closing bracket in `[]]` and `[^]]` does not count,
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//
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// and we should _not_ mark the second opening bracket in `[][]` and `[^][]`
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// as starting a new char set. ^ ^
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exists(int posBeforePrevClosingBracket |
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this.charSetDelimiter(index - 2, posBeforePrevClosingBracket) = true
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result = this.charSetStart(posBeforePrevClosingBracket).booleanNot()
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)
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else result = true
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else
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// if not, `pos` does in fact mark a real start of a character range
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result = true
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)
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)
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)
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}
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/** result denotes if the index is a left bracket */
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/**
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* Helper predicate for chars that could be character-set delimiters.
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* Holds if the (non-escaped) char at `pos` in the string, is the (one-based) `index` occurrence of a bracket (`[` or `]`) in the string.
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* Result if `true` is the char is `[`, and `false` if the char is `]`.
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*/
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boolean charSetDelimiter(int index, int pos) {
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pos =
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rank[index](int p |
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